The smallest number which when devided by 24,36 and 64 leaves 4 as remainder in each case. Question The smallest number which when devided by 24,36 and 64 leaves 4 as remainder in each case. in progress 0 Math Caroline 3 weeks 2021-10-01T13:57:43+00:00 2021-10-01T13:57:43+00:00 2 Answers 0 views 0

## Answers ( )

Answer:

Step-by-step explanation:

Let’s call the number x

Therefore when x is divided by 24 36 64 leaves reminder as 4

So x is a factor of 20 32 60

So we will find the HCF of 20,32,60

And that is 4

Hence the answer is 4

The smallest number divisible by all 24, 36, 54 is:

LCM(24, 36, 54) = 216

Thus, to get 5 as remainder, we need to add 5 to 216 (as 216 is the smallest number which gives remainder 0 when divided by 24 or 36 or 54)

216 + 5 = 221

For 12, 221 gives 18 as quotient and 5 as remainder

For 36, 221 gives 6 as quotient and 5 as remainder

For 54, 221 gives 4 as quotient and 5 as remainder

Hence, 221 is required number